find the largest number which divides 2271 and 3079 and 3355 leaving remainder 10,20 and 30 respectively
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Hiii friend,
2271 - 10 = 2261
3079 -20 = 3059
And,
3355 - 30 = 3325
Prime factorisation of 2261 = 7 × 17 × 19
Prime factorisation of 3059 = 7 × 19 × 23
Prime factorisation of 3325 = 7 × 19 × 25
HCF of 2261 , 3059 and 3325 = 7 × 19 = 133
Therefore,
The required largest Number = HCF of 2261,3059,3325 = 133
HOPE IT WILL HELP YOU....... :-)
2271 - 10 = 2261
3079 -20 = 3059
And,
3355 - 30 = 3325
Prime factorisation of 2261 = 7 × 17 × 19
Prime factorisation of 3059 = 7 × 19 × 23
Prime factorisation of 3325 = 7 × 19 × 25
HCF of 2261 , 3059 and 3325 = 7 × 19 = 133
Therefore,
The required largest Number = HCF of 2261,3059,3325 = 133
HOPE IT WILL HELP YOU....... :-)
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