Question

find the largest number which divides 2271 and 3079 and 3355 leaving remainder 10,20 and 30 respectively

Answer 1

Hiii friend,

2271 - 10 = 2261

3079 -20 = 3059

And,

3355 - 30 = 3325


Prime factorisation of 2261 = 7 × 17 × 19

Prime factorisation of 3059 = 7 × 19 × 23


Prime factorisation of 3325 = 7 × 19 × 25



HCF of 2261 , 3059 and 3325 = 7 × 19 = 133


Therefore,


The required largest Number = HCF of 2261,3059,3325 = 133



HOPE IT WILL HELP YOU....... :-)