Question

Find the largest number which divides 248 and 1032 leaving remainder 8 in each case

Answer 1

The number will be the HCF of 248 - 8 and 1032 - 8.

240=2*2*2*2*3*5

1024=2*2*2*2*2*2*2*2*2*2

So HCF of 240 and 1024= 2*2*2*2=16

So 16 is the answer.

Answer 2

Thus so

It will be the HCF of

248 - 8 = 240

1032 - 8 = 1024

➡ thus by EUCLIDS DIVISION ALGORITHM

➡ a = bq + r
.
. 1024 = 240 ❌ 4 + 64

. 240 = 64 ❌ 3 + 48

64 = 48 ❌ 1 + 16

. 48 = 16 ❌ 3 + 0

➡ THUS THE HCF WILL BE 16 .

Hope it helps .

Mark as brainliest if helpful .