Question

Find the largest number which divides 318 and 739 leaving remainder 3 and 4 respectively.

Answer 1

since on dividing 318 by the required no.  the remainder is 3 
then 318-3 ie. 315 wil be exactly divisible by the required no.
Similarly,739-4 ie. 735 will be exactly divisible by the required no.
PRIME FACTORISATION OF 
315=3 * 3 * 5 * 7
735=7 * 3 * 5* 7 
H.C.F OF 315 AND 735 = 3 * 5 * 7 =105  

Answer 2

Answer:

105 is the largest number which divides 318 and 739 leaving remainder 3 and 4 respectively.

Step-by-step explanation:

To find : The largest number which divides 318 and 739 leaving remainder 3 and 4 respectively ?

Solution :

Number which divides 318 and 739 leaving remainder 3 and 4 respectively

318-3=315

739-4=735

Now, We find the Highest common factor of the numbers 315 and 735

$315=3\times 3\times 5\times 7$

$735=3\times 5\times 7\times 7$

$HCF(315,735)=3\times 5\times 7$

$HCF(315,735)=105$

Therefore, 105 is the largest number which divides 318 and 739 leaving remainder 3 and 4 respectively.