Math, asked by chandelreenarani1984, 20 days ago

Find the largest number which divides 438 and 606, leaving remainder 6 in each case.​

Answers

Answered by magical2
3

Answer:

24

Step-by-step explanation:

438-6=432

606-6=600

H.C.F of 432 and 600 is 24

so, the largest number which divides 438 and 606, leaving remainder 6 in each case is 24.

hope it will be helpful

Answered by manmeetmaan20
5

Answer:

24

Step-by-step explanation:

remainder = 6

subtract 6 from both the no.

→ 438-6 and 606 - 6

→ 432 and 600

Now , find the HCF of 432 and 600

432 = 2 × 2 × 2 × 2 × 3 × 3 × 3

600 = 2 × 2 × 2 × 3 × 5 × 5

common factors = 2 × 2 × 2 × 3

Highest common factor = 24

24 is the highest no. that divides 438 and 606 and leaves remainder 6

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