Find the largest number which divides 438 and 606, leaving remainder 6 in each case.
Answers
Answered by
3
Answer:
24
Step-by-step explanation:
438-6=432
606-6=600
H.C.F of 432 and 600 is 24
so, the largest number which divides 438 and 606, leaving remainder 6 in each case is 24.
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Answered by
5
Answer:
24
Step-by-step explanation:
remainder = 6
subtract 6 from both the no.
→ 438-6 and 606 - 6
→ 432 and 600
Now , find the HCF of 432 and 600
432 = 2 × 2 × 2 × 2 × 3 × 3 × 3
600 = 2 × 2 × 2 × 3 × 5 × 5
common factors = 2 × 2 × 2 × 3
Highest common factor = 24
24 is the highest no. that divides 438 and 606 and leaves remainder 6
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