find the largest number which divides 438 and 606 leaving remainder 6 in each case
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606-6=600=a
438-6=432=b
By Euclid's division lemma
a=bq+r
600=432*1+168
432=168*2+96
168=96*1+72
96=72*1+24
72=24*3+0
Hcf(600,432)=24
Therefore 24 is the highest no. Which divide 606 and 438 leaving remainder 6.
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