Question

Solve the Equation
x÷10+y÷5= 14
And
x÷8+y÷6= 15

Answer 1

$\bold{ \underline{ \fbox{ \huge{ANSWER}}}}$

Topic;- Linear Equation in two variable

Question:-

$\bold{ \frac{x}{10} + \frac{y}{5} = 14}$



$\bold{ \frac{x}{8} + \frac{y}{6} = 15}$



Solving By Elimination method;




LCM of First Equation: 10 and 5 =) 10



LCM of Second Equation : 8 and 6=)24




Define First Equation:-



$\bold{ \frac{x}{10} + \frac{y}{5} = 14}$



(x+2y)/10=14



x+2y=140 (Equation A)



Define the Second Equation;



$\bold{ \frac{x}{8} + \frac{y}{6} = 15}$





(3x+4y)/24=16




3x+4y=360 (Equation b)



Solving the Equation a and b




Using Elimination method;



x+2y=140



3x+4y=360

x+2y=140 × 3

3x+4y=360. ×1

______________

3x+6y=420
3x+4y=360
__________
2y=60

y=60/2

y=30

Substitute the value of y in Another Equation!

3x+4y=360





3x+4(30)=360

3x+120=360

3x=360-120

3x=240

x=240/3

x=80

$\bold{ \underline{ conclusion}}$

X=80

y=30