Find the largest number which divides 546 and 764 leaving remainders 6 and 8 respectively
Answers
Answered by
82
546-6=540
764-8=756
then find HCF of
540=2²×3³×5
756=2²×3³×7
2×2×3×3×3=108
Therefore answer is 108
764-8=756
then find HCF of
540=2²×3³×5
756=2²×3³×7
2×2×3×3×3=108
Therefore answer is 108
sonu1432:
did u got it
Answered by
29
Step-by-step explanation:
The largest number that divides 546 and 764 leaving remainders 6 and 8 respectively is given by
highest common factor of 546 – 6 = 540 and 764 – 8 = 756.
The prime factorization of 540 and 756 are
540 = 2 × 2 × 3 × 3 × 3 × 5 = 2² × 3³ × 5
and
756 = 2 × 2 × 3 × 3 × 3 × 7 = 2² × 3³ × 7
∴ HCF = 2² × 3³ = 108
Hence, the largest number is 108.
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Question : Find the largest number which divides 546 and 764 leaving remainders 6 and 8 respectively.
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