five years hence the age of jacob will be three times that of son. five years ago jacob s age was seven times that of his son. what are thier present ages
Answers
Let son's age be x.
Son's age after 5 years.
x + 5
So,
According to given condition ,
Jacobs age = 3(x+5) = 3x+15
His present age = 3x +15 - 5
= 3x+10 ....................... (1)
Five years ago....
Son's age = x - 5
According to the given condition,
Jacobs age = 7(x - 5)
Jacobs age = 7x - 35
His present age = 7x - 35 + 5 =
7x - 30 . . . . . . . .. . . . . . (2)
So,
His sons present age is 10years.
Present age of Jacob=
3x + 10 ...............................from(1)
3(10)+10 = 30 + 10 = 40years.
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Final Answer :
The present ages of Jacob and Son are 40years and 10years.
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Answer:
Step-by-step explanation:
Given :-
The age of Jacob will be three times that of his son.
Solution :-
Let the present age of Jacob be be x year
And the present Age of his son be be y year
Five years Ago
Jacob’s age will be = x + 5 year
Age of his son will be = y + 5 year
According to the Question,
⇒ x + 5 = 3(y + 5)
Adding 5 to both side,
⇒ x = 3y + 15 - 5
⇒ x = 3y + 10 … (i)
Five years ago,
Jacob’s age= x - 5 year
His son’s age = y - 5 year
Jacob’s age was seven times that of his son
⇒ x - 5 = 7(y - 5)
Putting the value of x from equation (i) we get
⇒ 3y + 10 - 5 = 7y - 35
⇒ 3y + 5 = 7y – 35
⇒ 3y - 7y = - 35 - 5
⇒ -4y = - 40
⇒ y = - 40/-4
⇒ y = 10 year
Putting the value of y in equation we get
⇒ x = 3 × 10 + 10
⇒ x = 40 years
Present age of Jacob = 40 years,
Present age of his son = 10 years.