Which term of the A.P. 3, 12, 21, 30,…. will be 90 more than its 50th term ?
Answers
Answered by
42
a = 3
d = 9
Let the required term be n
=> Tn = T50 + 90
=> Tn = a + 49d + 90
=> Tn = 3 + 49×9 + 90
=> Tn = 3 + 441+ 90
=> Tn = 534
=> a + (n-1) d = 534
=> 3 + (n-1) 9 = 534
=> (n-1) 9 = 531
=> n - 1 = 59
=> n = 60
So,
60th term of the given AP is 90 more than the 50th term
d = 9
Let the required term be n
=> Tn = T50 + 90
=> Tn = a + 49d + 90
=> Tn = 3 + 49×9 + 90
=> Tn = 3 + 441+ 90
=> Tn = 534
=> a + (n-1) d = 534
=> 3 + (n-1) 9 = 534
=> (n-1) 9 = 531
=> n - 1 = 59
=> n = 60
So,
60th term of the given AP is 90 more than the 50th term
rohitkumargupta:
Bro
Answered by
37
HELLO DEAR,
A.P. 3, 12, 21, 30,….
a = 3 ,d = 9
a50 = [ 3 + (50-1)9]
==> (3 + 441)
==> 444
now ,
an = 444 + 90
==> [3 +(n-1)9] = 534
==> 9n -6 = 534
==> 9n = 540
==> n = 540/9
==> n = 60
I HOPE ITS HELP YOU DEAR,
THANKS
A.P. 3, 12, 21, 30,….
a = 3 ,d = 9
a50 = [ 3 + (50-1)9]
==> (3 + 441)
==> 444
now ,
an = 444 + 90
==> [3 +(n-1)9] = 534
==> 9n -6 = 534
==> 9n = 540
==> n = 540/9
==> n = 60
I HOPE ITS HELP YOU DEAR,
THANKS
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