Question

. Find the largest number which divides 615

and 963 leaving remainder 6 in each case.

Answer 1

To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.

Consider HCF be x.

In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases.

609 = 3 x 3 x 29

957= 3 x 11 x 29

⇒ x = 3 x 29 = 87

∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87

Answer 2

Answer:

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