Find the largest number which divides 62,132, and 237 to leave the same remainder in each case.
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the correct answer is "5"
62/5= 12*5 + 2
132/5= 26*5+ 2
237/5= 47*5+ 2
62/5= 12*5 + 2
132/5= 26*5+ 2
237/5= 47*5+ 2
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ᴛʜᴇ ᴄᴏʀʀᴇᴄᴛ ᴀɴsᴡᴇʀ ᴡɪʟʟ ʙᴇ 5 .................
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