Question

Find the least number which when divided by 16, 6 and 11 leaves the same remainder "5" in each case.

Answer 1

correct answer is "533"

533= 16*33+5
533=6*88+5
533=11*48+5

I hope it will helpful for you

Answer 2

The least number which when divided by 16 , 6 and 11 leaves the same remainder 5 in each case is 533

Given :

A number is divided by 16 , 6 and 11

To find :

The least number which when divided by 16 , 6 and 11 leaves the same remainder 5 in each case

Solution :

Step 1 of 3 :

Prime factorise the given numbers

6 = 2 × 3

16 = 2 × 2 × 2 × 2

11

Step 2 of 3 :

Find LCM of 16 , 6 and 11

LCM of 16 , 6 and 11

= 2 × 2 × 2 × 2 × 3 × 11

= 528

Step 3 of 3 :

Find the number

Since the number which when divided by 16 , 6 and 11 leaves the same remainder 5 in each case

Hence the required least number

= 528 + 5

= 533

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