Question

Find the largest positive integer that will divide 122,150 and 115 leaving remainder 5,7,11. respectively?

Answer 1

Heya !!!

122 - 5 = 117

150 - 7 = 143

115 - 11 = 104

Prime factorisation of 117 = 3 × 3 × 13

Prime factorisation of 143 = 13 × 11

Prime factorisation of 104 = 2 × 2 × 2 × 13

Required Number = HCF of 117 , 143 and 104 = 13.



Hence,


The largest Number that Divide 122 , 150 , 115 leaving Remainder 5,7,11 is 13.

HOPE IT WILL HELP YOU...... :-)

Answer 2

HEY FRIEND

HERE IS YOUR ANSWER

•122-5=117

•150-7=143

•115-11=104

NOW TAKE THE HCF :

117=3×3×13

143=11×13

104=2×2×2×13

HCF=13

The largest no. that will divide 122,150,115 leaving remainder 5,7 and 11 respectively is 13.

HOPE THIS HELPS YOU ☺