find the largest term of the AP whose first two terms are 2/5 and 12/23
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If the he two term are HP are 2/5 and 12/23
Here for first term of the corresponding AP is a = 5/2
and the 2nd term of corresponding AP is 23/12
Therefore
Common difference d= 23 12 - 5 2 = 23 - 30 12 = -7 12
Let the positive smallest term of AP be nth term.
Therefore 5 2 + ( n - 1 ) * (-7 12 ) ≥ 0 - 7 12 * ( n - 1 )≥ - 5 2 ( n - 1 ) ≤ 5 2 * 12 7 n - 1 ≤ 30 7 = 4 . 2 n - 1 = 4 [ since n is an integer n = 1 + 4 = 5 ]
fifth term of AP = 52 + ( 5 - 1 ) * (-7 12 ) = 52 - 73 = 15 - 146 = 16
largest term of HP = 5th term
therefore fifth term of HP = 6
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Answer:
answer is 6
first convert HP into AP
then find the first 6 terms of AP
then analysis the largest positive term
answer comes to be 6
don't by it own.....
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