find the largest that divides 220, 313 and 716 leaving remainder 3 in each case
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Answered by
24
Answer:
First we will subtract 3 from each no.-
220 - 3 = 217
313 - 3 = 310
716 - 3 = 713
Then, we will find the HCF of 217,310,713
217 = 7*31
310 = 2*5*31
713 = 23*31.
So, the HCF of 217,310,713 is 31.
So, therefore, the largest no. that divides 220,313, and 716 is 31.
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Answered by
8
First we will subtract 3 from all the numbers as they leave a reminder of 3.
220 - 3 = 217
313 - 3 = 310
716 - 3 = 713
Then, we will find the HCF of 217,310,713
217 = 7x31
310 = 2x5x31
713 = 23x31.
The HCF of 217,310,713 is 31.
Therefore the largest number dividing 220 313 and 716 leaving a reminder 3 is 31
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