find the largest three digit number which is exactly divisible by 39
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Answer:
999 = 120 × 8 + 39 so, 39 is remainder. So 960 is greatest three digit number divisible by 8, 10, & 12. How do I find the greatest 3-digit number which is divisible by 6, 12, 18?
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your perfect answer is 975..
because......
975÷39=25
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