find the last two digits of 28^64
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Answer:
56
Step-by-step explanation:
28^64
Can be written as
2^64 x 14^64
- last two digits of 28^64=last two digits of 2^64 x 14^64
So now
((2^10)^6 x 2^4) x ((2^64) x 7^64)
last two digits of all
(24^6 x 2^4) x (24^6 x 2^64) x 7^64)
(76x16) x (76x16)x 01
( As 7 is prime number and special case The number divusible by 4 will always have last two digits 01)
16 x 16 x 1
256
- Last two digits are 5 and 6
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