find the lateral area and surface area of a cylinder with a base area of 493π and a height that is 2 times the radius
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sorry l dont no this answer
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Answer:-
LSA OF CYLINDER IS 2πrh And TSA OF CYLINDER IS 2πr(h+r)
given 2πr =493π and it's height is 2 times of it.
radius=493÷2=246.5 so it's 2 times is 493
Hence, 2πrh=493π×493=243049
2πr(h+r)=493π(493+246.5)
=493π×739.5
=364573.5
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