Find the lateral curved surface area of a cylindrical petrol storage tank that 4.2m in diameter and 4.5 metre height. How much steel was actually used if 1/12 of steel actually used was wasted in making the closed tank?
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Solution :-
Height of tank = 4.5 m
Diameter = 4.2
Therefore ,
Radius = 4.2/2 = 2.1m
CSA of Cylinder = 2πrh
CSA of cylinder = 2 * 22/7 * 2.1 * 4.5 = 59.4 sq.m
Hence , CSA of cylinder = 59.4 sq.m
Now , TSA of cylinder = 2πr( r + h)
TSA of cylinder = 2 * 22/7 * 2.1 ( 2.1 + 4.5)
TSA of cylinder = 2 * 22 * 0.3 * 6.6
TSA of cylinder = 87.12 sq.m
• Let the amount of steel used in making tank be x
Steel wasted = x/12
According to the question ,
Amount of steel required - Amount of steel wasted = TSA of tank
x - x/12 = 87.12
12x - x/12 = 87.12
11/12x = 87.12
x = 87.12 * 11/12
x = 95.04 sq.m
Hence , 95.04 sq.m steel is used in making tank
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