Question

Find the lateral surface area of a cuboid whose dimensions are 16 cm x 11.5 cm x 2.8 cm.
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Answer 1

Given :

• Dimensions of cuboid = 16 cm * 11.5 cm * 2.8 cm

To find :

• LSA of cuboid

Solution :

Given,

Length of cuboid, l = 16 cm

Breadth of cuboid, b = 11.5 cm

Height of cuboid, h = 2.8 cm

Now we know that,

LSA of cuboid = 2 * (l + b) * h

⇒  LSA of cuboid = 2 * (16 + 11.5) * 2.8

⇒  LSA  of cuboid = 2 * 27.5 * 2.8

⇒  LSA of cuboid = 154 cm²

Therefore,

LSA of cuboid = 154 cm²

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Some more formulas :

TSA of cuboid = 2(lb + bh + hl)

LSA of cuboid = 2(l + b)h

Volume of cuboid = l * b * h

Diagonal of cuboid = √(l² + b² + h²)

Volume of cube = a³

Answer 2

Answer:

$\: \: \boxed{\boxed{\rm{\mapsto \: \: \: Firstly \: let's \: understand \: the \: concept \: used}}}$

Here the concept of LSA of Cuboid has been used. According to this, when we have Length, Breadth and Height we can simply apply those values and find the LSA of Cuboid.

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★ Formula Used :-

$\boxed{\boxed{\large{\bf{LSA \: of \: Cuboid \: = \: 2 \: \times \: (L + B) \: \times \: h}}}}$

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★ Question :-

Find the lateral surface area of a cuboid whose dimensions are 16 cm x 11.5 cm x 2.8 cm.

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★ Solution :-

Given,

Let's derive the dimensions from the values.

» Length of the cuboid = 16 cm

» Breadth of the cuboid = 11.5 cm

» Height of the cuboid = 2.8 cm

Now let's find the LSA :-

➺ LSA of Cuboid = 2 × (L + B) × h

➺ LSA of Cuboid = 2 × (16 + 11.5) × 2.8

➺ LSA of Cuboid = 2 × 27.5 × 2.8

➺ LSA of Cuboid = 154 cm²

$\large{\boxed{\rm{\leadsto \: \: Hence, \: the \: LSA \: of \: Cuboid \: is \: \boxed{\bf{154 \: cm^{2}}}}}}$

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$\boxed{\boxed{\rm{\mapsto \: \: Reference \: as \: Supplementary \: Counsel \: }}}$

• TSA of Cuboid = 2(LB + BH + LH)

• TSA of Cube = 6 × (Side)²

• CSA of Cube = 4 × (Side)²

• Volume of Cube = (Side)³

• Volume of Cuboid = Length × Breadth × Height

• Volume of Cylinder = πr²

• Volume of Cone = ⅓ × πr²h