Find the lateral surface area of two pillars if height of the pillar is 7m and radius of the base is 1m?
Answers
Answer:
44m^2
Step-by-step explanation:
r = 1m
h. = 7m of a pillar
CSA of a cylinder = 2πrh
2 × 22/7 × 1 × 7
= 2× 22
= 44 m^2
The lateral surface area of the two pillars is 88 m²
Given:
The height of the pillar is 7m and the radius of the base is 1m
To find:
Find the lateral surface area of two pillars
Solution:
Formula used:
The lateral surface area of a cylinder = 2πrh
Where r = radius and h = height
Given the height of the pillar = 7m
The radius of the base of the pillar = 1m
By the given formula,
The lateral surface area of a cylinder = 2πrh
Leteral surface area of one pillar = 2(22/7)7(1) = 44 m²
The lateral surface area of two pillars = 2 × 44 m² = 88 m²
Therefore,
The lateral surface area of the two pillars is 88 m²
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