Question

find the LCM 5a²bc³and 4ab²c​

Answer 1

Answer:

$20 {a}^{2} {b}^{2} {c}^{3}$

Step-by-step explanation:

LCM of 5, 4 = 20

LCM of a²,a = a²

LCM of b², b = b²

LCM of c^3 , c = c^3.

Answer 2

Solution(By Examveda Team)

In Give Question,

A + B = 8 ---- (i)

A + C =13 -----(ii)

B + D = 8 ----(iii)

C - D = 6 ----(iv)

Therefore equation (i) and (iii) are equal

A + B = B + D

=> A = D

Therefore, equation (iv) can be C - A = 6 ----- (v)

Now solving equation (ii) and (v), We Get C = 9.5 and A = 3.5

Put this value of A in equation in (i) B = 4.5 and value of C in equation (iv) we get D = 3.5

A = 3.5

B = 4.5

C = 9.5

D = 3.5

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