Math, asked by akshay561, 1 year ago

Find the lcm and hcf of 15,18,45 by prime factorization method

Answers

Answered by faisal1231
5
15=3×5
18=2×3×3
45=3×3×5

hcf=3
lcm=2×3×3×5=90
Answered by yinc12
4
Hi!!

LCM of 15,18,45

      3  |   15   ,   18    ,   45
      3  |     5   ,     6    ,    15
      3  |     5   ,     2    ,     5
      2  |     5   ,     1    ,     5
      5  |     1   ,     1    ,     1

∴ LCM of 15, 18, 45 = 3 x 3 x 3 x 2 x 5
                                 = 27 * 10
                                 = 270

HCF of 15, 18, 45
>>
Factors of 15 ⇒ 1, 3, 5, 15
Factors of 18 ⇒ 1, 2, 3, 6, 9, 18
Factors of 45 ⇒ 1, 3, 5, 9, 15
Factors common in all ⇒ 1,3
∴ HCF of 15, 18, 45 = 1 x 3 = 3

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yinc12: EDIT ^^ I took an extra 3 sorry for that, SO LCM will be 3 x 3 x 2 x 5 = 90
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