Find the lcm and hcf of 15,18,45 by prime factorization method
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5
15=3×5
18=2×3×3
45=3×3×5
hcf=3
lcm=2×3×3×5=90
18=2×3×3
45=3×3×5
hcf=3
lcm=2×3×3×5=90
Answered by
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Hi!!
LCM of 15,18,45
3 | 15 , 18 , 45
3 | 5 , 6 , 15
3 | 5 , 2 , 5
2 | 5 , 1 , 5
5 | 1 , 1 , 1
∴ LCM of 15, 18, 45 = 3 x 3 x 3 x 2 x 5
= 27 * 10
= 270
HCF of 15, 18, 45
>>
Factors of 15 ⇒ 1, 3, 5, 15
Factors of 18 ⇒ 1, 2, 3, 6, 9, 18
Factors of 45 ⇒ 1, 3, 5, 9, 15
Factors common in all ⇒ 1,3
∴ HCF of 15, 18, 45 = 1 x 3 = 3
Hope you got the answer !
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LCM of 15,18,45
3 | 15 , 18 , 45
3 | 5 , 6 , 15
3 | 5 , 2 , 5
2 | 5 , 1 , 5
5 | 1 , 1 , 1
∴ LCM of 15, 18, 45 = 3 x 3 x 3 x 2 x 5
= 27 * 10
= 270
HCF of 15, 18, 45
>>
Factors of 15 ⇒ 1, 3, 5, 15
Factors of 18 ⇒ 1, 2, 3, 6, 9, 18
Factors of 45 ⇒ 1, 3, 5, 9, 15
Factors common in all ⇒ 1,3
∴ HCF of 15, 18, 45 = 1 x 3 = 3
Hope you got the answer !
Plzz mark as Brainliest!
Thanks! :)
yinc12:
EDIT ^^ I took an extra 3 sorry for that, SO LCM will be 3 x 3 x 2 x 5 = 90
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