Find the LCM and HCF of 336 and 54 and verify that LCM×HCF=Product of the two numbers
Answers
Answered by
429
Hi ,
Let a = 336 ,
b = 54
Expressing a and b as a product of
prime factors
336 = 2 × 2 × 2× 2 × 3 × 7 = 2^4 × 3 × 7
54 = 2 × 3 × 3 × 3 = 2 × 3^3
HCF ( 336 , 54 ) = 2 × 3 = 6
LCF( 336 , 54 ) = 2^4 × 3^3 × 7 = 3024
We know that ,
_____________________________
For any two positive integers a and b .
HCF( a , b ) × LCM( a , b ) = a × b
_____________________________
Verification :
------------------
HCF( 336 , 54 ) × LCM( 336 , 54 )
= 6 ×3024
= 18144 -----( 1 )
a × b = 336 × 54 = 18144 ----( 2 )
Therefore ,
( 1 ) = ( 2 )
I hope this helps you.
:)
Let a = 336 ,
b = 54
Expressing a and b as a product of
prime factors
336 = 2 × 2 × 2× 2 × 3 × 7 = 2^4 × 3 × 7
54 = 2 × 3 × 3 × 3 = 2 × 3^3
HCF ( 336 , 54 ) = 2 × 3 = 6
LCF( 336 , 54 ) = 2^4 × 3^3 × 7 = 3024
We know that ,
_____________________________
For any two positive integers a and b .
HCF( a , b ) × LCM( a , b ) = a × b
_____________________________
Verification :
------------------
HCF( 336 , 54 ) × LCM( 336 , 54 )
= 6 ×3024
= 18144 -----( 1 )
a × b = 336 × 54 = 18144 ----( 2 )
Therefore ,
( 1 ) = ( 2 )
I hope this helps you.
:)
Answered by
23
Answer:
18144
Step-by-step explanation:
LCM *HCF =PRODUCT OF THE TWO NUMBER
a= 336
b= 54
366=2^4*3*7
54 =2*3^3
HCF=6
LCM= 3024
LCM *HCF =Product of two no's
----)6*3024
---)18144.
hence proved or verified
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