Math, asked by sonamkumari93461, 2 months ago

Find the LCM and HCF of the following: (i) 25 × 54 × 72 × 136 and 23 × 56 × 7 × 173 (ii) a5 × b2 × c2 × d5 and a7 × b3 × e × f3 where a, b, c, d, e, and f are prime

Answers

Answered by skmuffiskmuffi
9

Answer:

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Answered by chitrad6424
2

Step-by-step explanation:

I) 72= 2*2*2*3*3

56= 2*2*2*7

98= 2*7*7

HCF :

2(common in all the three)

LCM :

2*2*2*7 =56

2*2*2*3*3=63

56*63 = 3528

lcm = 3529

2). let's find hcf first

in both the numbers take the common, that is A and B are common with a^5 and b^2

HCF = a^5 and b^ 2

now,

let's find lcm

prime numbers in above numbers are ;

a, b, c, d e, f

highest number : a^7,b^3,c^2,d^5,e^1,f^3

lcm = a^7,b^3,c^2,d^5,e^1,f^3

HENCE PROVED

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