Find the lcm and hcf of the following integers by applying the prime factorisation method:
(1) 12, 15 and 21
Answers
Answered by
7
Hi mate your answer is
HCF=1
LCM=2×2×3×5×7
=420
as, hcf
12=2×2×3
15=3×5
21=3×7
hope it helps you
HCF=1
LCM=2×2×3×5×7
=420
as, hcf
12=2×2×3
15=3×5
21=3×7
hope it helps you
quantumhero:
hcf=1 becoz nothing is common in all the cases
yes
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