Find the LCM and HCF of the following pairs of integers and verify that LMC × HCF = Product of the integers:
(i) 26 and 91
(ii) 510 and 92
(iii) 336 and 54
Answers
Answer:
Step-by-step explanation:
LCM * HCF = Product of the numbers
Step-by-step explanation:
(i) 26 & 91
Factors of 26 = 2 * 13
Factors of 91 = 7 *13
So LCM = 2 * 7 * 14 = 182
HCF = 13
LCM * HCF = 182 * 13 = 2366
Product of the numbers = 26 * 91 = 2366
Hence proved that LCM * HCF = Product of the numbers
(ii) 510 and 92
Factors of 510 = 2 * 3 * 5 * 17
Factors of 92 = 2 * 2 * 13
So LCM = 2 * 2 * 3 * 5 * 17 * 23 = 23460
HCF = 2
LCM * HCF = 23460 * 2 = 46920
Product of the numbers = 510 * 92 = 46920
Hence proved that LCM * HCF = Product of the numbers
(iii) 336 and 54
Factors of 336 = 2 * 2 * 2 * 2* 3 * 7
Factors of 54= 2 * 3 * 3 * 3
So LCM = 2 * 2 * 2 * 2 * 3 * 3 * 7 = 3024
HCF = 2 * 3 = 6
LCM * HCF = 3024 * 6 = 18144
Product of the numbers = 336 * 54 = 18144
Hence proved that LCM * HCF = Product of the numbers