Find the LCM and HCF of the following pairs of integers and verify that LCM×HCF=product of the two numbers. 26 and 91 purn Sar long metho
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Given 2 numbers are 26 and 91
Prime factors of 26=13×2
Prime factors of 91=13×7
So from the prime factors LCM=13×2×7=182
HCF=13
Product of the numbers =26×91
2366
Product of LCM and HCF =182×13
2366
LHS=RHS
Hence proved
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