Question

find the LCM and HCF of the following pairs of integers and verify that LCM and HCF = product of the two numbers numbers 2) 510 and 92​

Answer 1

Explanation:

As we know the formula :-

L.C.M×H.C.F=Product of numbers

L.C.M×H.C.F=510 and 92

(to find H.C.F of these numbers 1st use Euclid Division algorithm then put it according to the formula of the above given)

Which is a=bq+r

Now,

510=>92×5+50

92=>50×1+42

50=>42×1+8

42=>8×5+2

8=>2×4+0

H.C.F=2

Now

L.C.M×2=510 ×92

L.C.M=510×92/2

L.C.M=255×92

L.C.M=>23460

Hence the, H.C.F=2 and L.C.M=>23460

hope it may helpful.

Answer 2

Answer:

The number can be expressed as the product of prime factors as

510 = 2 x 3 x 5 x 17

92 = 22 x 23

HCF(510,92) = 2

LCM(510,92) = 22 x 3 x 5 x 17 x 23 = 23460

HCF x LCM = 2 x 23460 = 46920

510 x 92 = 46920

510 x 92 = HCF x LCM

Hence Verified