Question

Find the Lcm and HCF of the the following pairs of integer and varify that LCM ×HCF= product of the two numbers

510 & 92​

Answer 1

Answer:

510=92×5+50

92=50×1+42

50=42×1+8

42=8×5+2

8=2×4+0

hcf is 2

Step-by-step explanation:

product of LCMand HCF is equals to product of two numbers

510×92=2×m

m=510×92/2

m=510×46

m=23460

Answer 2

$\huge\sf\pink{Answer}$

☞ HCF = 2

☞ LCM = 23460

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ 510 and 92

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

◈ Its HCF and LCM and also verify that Product of two numbers = LCM × HCF

$\rule{110}1$

$\huge\sf\purple{Steps}$

So now, We can use the prime factorisation method,

➝ 510 = 2 × 5 × 3 × 17

➝ 92 = 2 × 2 × 23

So now the HCF is the product of the least power of the common factors,that is,

≫ $\sf\red{HCF(510,92) = 2}$

And LCM Is the product of the highest power of all the factors, that is,

LCM(510,92) = 2² × 3 × 17 × 23 × 5

≫ $\sf\orange{LCM(510,92) = 23460}$

$\rule{100}{1.5}$

Verification

»» Product of two numbers = HCF × LCM

»» 510 × 92 = 2 × 23460

»» 46920 = 46920

»» LHS = RHS

$\textsf{Hence Verified!!}$

$\rule{170}3$