Math, asked by achalmohod01, 6 days ago

Find the LCM and HCF of two integers 1015, 1165 ​

Answers

Answered by chandanyadav958
0

Step-by-step explanation:

lcm of 1015 and 1165 is 236495

and HCF is 5

Answered by sheeb12ansari
0

Given: The two integers are1015\ and\ 1165.

We have to find the LCM and HCF of the above integers.

We are solving in the following way:

We have,

The two integers are1015\ and\ 1165.

a) The LCM of the above integers will be:

Prime Factorization of  1015is:

5 \times 7 \times 29  =>  5^1 \times7^1 \times 29^1

Prime Factorization of 1165 is:

5 \times 233  =>  5^1  \times 233^1

For each prime factor, we will find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is:

5, 7, 29, 233

Multiplying these factors together to find the LCM:

LCM: 5 \times 7 \times 29 \times 233 = 236495

In exponential form:

LCM =5^1 \times 7^1 \times 29^1 \times 233^1 = 236495

LCM = 236495

Hence, the LCM of the above numbers is236495.

b) The HCF of 1015\ and\ 1165 will be:

As we know that the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

The factors of 1015 are: 1, 5, 7, 29, 35, 145, 203, 1015

The factors of 1165 are: 1, 5, 233, 1165

Then the greatest common factor is 5.

Hence, the LCM of the above numbers is236495.

And the HCF of the above numbers is5.

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