Math, asked by subachandraghari, 4 months ago

find the LCM of the following Polynomial
(XV)
6x2 – X – 1, 3x2 + 7x + 2 and 2x2 + 3x - 2
(xvi) x2 + 2x – 15, x2 + 9x + 20 and x2 + 4x – 21​

Answers

Answered by Anonymous
7

Answer:

Answer

x

2

−3x+2=x

2

−2x−x+2

x(x−2)−1(x−2)=(x−2)(x−1)

Now

x

2

−4x+3=x

2

−3x−x+3

x(x−3)−1(x−3)=(x−3)(x−1)

Thus, the only common factor is (x-1)

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