Find the LCM of the following polynomials
2 x 3 - 128,, X2 - 9 X + 20, X2- 16
Answers
Answered by
4
Answer:
Step-by-step explanation:
2x^3-128=2(x^3-64)
=2(x-4)(x^2+4x+16)
X^2-9x+20
=x^2-4x-5x+20
=x(x-4)-5(x-4)
=(x-4)(x-5)
LCM=2(x-4)(x^2+4x+16)(x-5)
LCM=(2x^3-128)(x-5)
Answered by
4
Answer:
Step-by-step explanation:
2x^3-128=2(x^3-64)
=2(x-4)(x^2+4x+16)
X^2-9x+20
=x^2-4x-5x+20
=x(x-4)-5(x-4)
=(x-4)(x-5)
LCM=2(x-4)(x^2+4x+16)(x-5)
LCM=(2x^3-128)(x-5)
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