Question

find the lcm of x^2-4 and x^2-16

Answer 1

LCM of x²-4* and x²-16 is 4

Answer 2

$Heya$‼

a) • $x^2-4$
$=x(x-4)$ ...(1)

b) • $x^2-16$
$=x^2-4^2$
$=(x-4)(x+4)$ ...(2)

From (1) and (2) expressions :-
L.C.M. $(x^2-4 , x^2-16)$
$=x*(x-4)*(x+4)$
$=x(x-4)(x+4)$

Hence, L.C.M. of $(x^2-4 , x^2-16)$ is $x(x-4)(x+4)$.