Question

Find the least 5 digit number which on dividing by 6 9 12 and 18 leaves remainder 3 in each case

Answer 1

The required number divides

(6-3)3, ( 9-3)6,( 12-3)9 and (18-3)15.

To find the Least number you have to find the HCF of 3, 6, 9 and 15.

Therefore, 3= 3×1

6= 2×3

9=3×3

15= 3×5

So the HCF is 3 hence the least number is 3.

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