Question

Find the least coloumbs force between two electron at 1m apart

Answer 1

Solution :

⏭ Given:

✏ Two electrons are separated by distance 1m.

⏭ To Find:

✏ Electrostatic force between them.

⏭ Formula:

✏ As per coulomb's law, force exerts between two charged particles is given by...

$\bigstar \: \boxed{ \tt{ \large{ \pink{F = \frac{kq_1q_2}{ {r}^{2} }}}}} \: \bigstar$

⏭ Terms indication:

• F denotes electrostatic force
• q1 & q2 denotes charge on particles
• k denotes coulomb's constant
• r denotes distance between two charged particles

⏭ Calculation:

$\circ \sf \: k = 9 \times {10}^{9} \: N {m}^{2} {C}^{ - 2} \\ \\ \circ \sf \: charge \: on \: electron = 1.6 \times {10}^{ - 19} \: C \\ \\ \mapsto \sf \: F = \dfrac{k {q}^{2} }{ {r}^{2} } \\ \\ \mapsto \sf \: F = \frac{9 \times {10}^{9} \times {(1.6 \times {10}^{ - 19}) }^{2} }{ {(1)}^{2} } \\ \\ \mapsto \sf \: F = 9 \times 2.56 \times {10}^{ - 29} \\ \\ \mapsto \: \boxed{ \tt{ \red{Force = 23.04 \times {10}^{ - 29} \: N}}}$

⏭ Additional information:

• Force is a vector quantity.
• SI unit of force is N

Answer 2

Coulumb's Law :

$\bigstar \: \boxed{ \tt{ \large{ \orange{\leadsto{F = \frac{kq_1q_2}{ {r}^{2} }}}}}}$

• F denotes electrostatic force.

• q1 & q2 denotes charge on particles.

• k denotes coulomb's constant.

• r denotes distance between two charged particles.

$\begin{lgathered}\circ \sf \: k = 9 \times {10}^{9} \: N {m}^{2} {C}^{ - 2} \\ \\ \circ \sf \: charge \: on \: electron = 1.6 \times {10}^{ - 19} \: C \\ \\ \leadsto \sf \: F = \dfrac{k {q}^{2} }{ {r}^{2} } \\ \\ \mapsto \sf \: F = \frac{9 \times {10}^{9} \times {(1.6 \times {10}^{ - 19}) }^{2} }{ {(1)}^{2} } \\ \\ \leadsto \sf \: F = 9 \times 2.56 \times {10}^{ - 29} \\ \\ \leadsto \: \boxed{ \tt{ \blue{Force = 23.04 \times {10}^{ - 29} \: N}}}\end{lgathered}$