Question

Find the least coulomb's force in nature, for the charges placed 1m apart.
(q = e, 2.3x10-28N)

Answer 1

Answer:

In Electrostatics Coulomb give a formula of magnitude of force acting between two system of charges and was given by

F = q

1. /(Where E = Permittivity of given medium

and r = distance between 2 charges

The Force by which 2 charges in static condition are held together is called Coulombian force of attraction....

e

Explanation:

Answer 2

Find the least coulomb's force in nature, for the charges placed 1m apart..

solution : charge on electron is the smallest amount of charge existing in the nature. so least Coulomb's force will be appear only between two electrons.

charge on electron, q = 1.6 × 10^-19 C

seperation between two Electrons, r = 1 m

now least Coulomb's force, F = kq²/r²

= (9 × 10^9 × 1.6 × 10^-19 × 1.6 × 10^-19)/1²

= 9 × 2.56 × 10^-29 N

= 23.04 × 10^-29 N

= 2.3 × 10^-28 N

Therefore least Coulomb's force in the nature, for charges placed 1 m apart , is 2.3 × 10^-28 N

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