find the least multiple of 11 which when divided by 6, 7 and 10 leaves
the remainder 4 in each case.
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Answer:
x=360,x+4=364. 364 leaves remainder 4 when divided by 6,9,15 and 18. And is also a multiple of 7. Hence,364 is the least number satisfying all the conditions.
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Therefore 364 is the appropriate answer
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