find the least multiple of 13 which when divided by 5,8 and 12 leave the same remainder of 2 in each case?
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the least multiple of 13 on dividing by 4 5 6 7 and 8 leaves remainder 2 in each case is LCM of 4 5 6 7 and 8 equal 840 let required number be 840k +2 which is multiple of 13 point 3 + 2 equal to 2580 + 2 equal 2522
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