find the least multiple of 13 which when divided by 6 8 and 12 leaves 5 7 and 11 as remainders respectively?
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LCM (6, 9,15 & 18) + 4
= 180 + 4
= 184
BUT IT MUST BE ALSO DIVISIBLE BY 7
sO WE CAN SAY THAT NUMBER IS 180k+4
180K+4
= 175K+5K+4
175K IS DIVISIBLE BY 7
SO PUT ANY VALUE OF K IN 5K+ 4 SO THAT IT WILL BE DIVISIBLE BY 7
HENCE K = 2
ANSWER IS 180*2+4 = 364
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