two pipes a and b can fill a tank in 16 hours and 24 hours respectively and pipe c can empty the tank in 32 hours. if all the pipes are opened alternatively for 1 hour each then find the time taken to fill the tank.
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In one hour the water amount for each tap is :
A = 1/16
B = 1/24
C = 1/32
In one hour :
The amount in the tank is :
1/16 + 1/24 - 1/32 = 7/96
1 hour => 7/96
? = 1
96/7 × 1 = 13.71 hrs
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