Question

Find the least multiple of 23,which when divided by 18,21 and 24 leaves the remainder 7,10 and 13 respectively.

Answer 1

Answer :

(C)

605

Description :

Here (18 - 7) = 11, (11 - 0) = 11 and (14 - 3) = 11. L.C.M. of 18, 11 and 14 is 616. Let required number be 616k – 11. Least value of k for which (616k - 11) is divisible by 5 is k = 1 Required number = 616 x 1 - 11 = 616 - 11 = 605

or

Answer :

LCM of 18, 21 and 24 is 504 then 18-7=11 21-10=11 24-13=11 so common is 11 Require number is (504m 11)/23 (504*6 11)/23 = 3013

I hope my answer was satisfied

Answer 2

Answer:

Step-by-step explanation:

1- Take L. C. M of given no 18,21 and 24

2- use the formula

L. C. M*M -k/n where k=(no-remainder+2nd no-rem+3rd no-rem) /no of term

3- use the hit and trial method by putting the values M and check whether the no is divided by 23 or not