Question

Find the least multiple of 7 which leaves a remainder of 4 when divided by 6,9,15,18

Answer 1

Answer:

find the LCM of the given numbers and then add 4

Answer 2

Step-by-step explanation:

L.C.M. of 6, 9, 15 and 18 is 90.

Let required number be 90k + 4, which is multiple of 7.

Least value of k for which (90k + 4) is divisible by 7 is k = 4.

∴Required number = (90 x 4) + 4 = 364.