Question

find the least natrual number which when divided by25, 40, and 60 leaves a remainder8

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Answer 1

Answer:

LCM of 25, 40 & 60 = 2*2*2*5*5*3 = 8*25*3 = 200*3 = 600. 600 perfectly divides the 3 numbers and leaves the remainder as 0. So, 600+8 = 608 is the smallest number which leaves remainder 8 when divided by 20, 40 & 60.

Answer 2

Answer:

hilu

Step-by-step explanation:

600 perfectly divides the 3 numbers and leaves the remainder as 0. So, 600+8 = 608 is the smallest number which leaves remainder 8 when divided by 20, 40 & 60.

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