find the least no by which 1392 should be multiplied to make it a perfect square. show methods
insiyahr:
pls ans fast
Answers
Answered by
16
write the given number as product of the prime numbers
1392 = 2*2*2*2*3*29
= (2*2)*(2*2) *3 *29
3 and 29 are not have pairs
if we multiply the given number with (3*29) it becomes perfect square
1392 *3*29 =2*2*2*2*3*3*29*29
= (2*2*3*29)²
=(348)²
1392 = 2*2*2*2*3*29
= (2*2)*(2*2) *3 *29
3 and 29 are not have pairs
if we multiply the given number with (3*29) it becomes perfect square
1392 *3*29 =2*2*2*2*3*3*29*29
= (2*2*3*29)²
=(348)²
Answered by
16
For such type of problems,
First you have to factorise the number given
Factorise 1392
1392 = 2*2*2*2*3*29.
So find the numbers without pairs..
That is 3 and 29
So as you have two numbers multiply both.
3 * 29 = 87.
Now you have got the number which you have to multiply with 1392 to become perfect square.
Therefore we will check it out!
1392 * 87 = 121104, which is a perfect square.
Thus, the answer is 87.
Thanks
First you have to factorise the number given
Factorise 1392
1392 = 2*2*2*2*3*29.
So find the numbers without pairs..
That is 3 and 29
So as you have two numbers multiply both.
3 * 29 = 87.
Now you have got the number which you have to multiply with 1392 to become perfect square.
Therefore we will check it out!
1392 * 87 = 121104, which is a perfect square.
Thus, the answer is 87.
Thanks
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