The coordinates of the point that is two third away from (-4,3) to (5,7) is
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Let the required coordinate of the point is (x,y). Then the point cuts the line segment joining the points (-4,3) and (5,7) externelly in the ratio of 2:3.
∴, x=(mx₂-nx₁)/(m-n) and y=(my₂-ny₁)/(m-n) where
(x₁,y₁)=(-4,3) and (x₂,y₂)=(5,7) and m:n=2:3
x={2.5-3.(-4)}/(2-3)=(10+12)/(-1)=-22
y=(2.7-3.3)/(2-3)=(14-9)/(-1)=-5
∴, the required coordinate is: (-22,-5)
∴, x=(mx₂-nx₁)/(m-n) and y=(my₂-ny₁)/(m-n) where
(x₁,y₁)=(-4,3) and (x₂,y₂)=(5,7) and m:n=2:3
x={2.5-3.(-4)}/(2-3)=(10+12)/(-1)=-22
y=(2.7-3.3)/(2-3)=(14-9)/(-1)=-5
∴, the required coordinate is: (-22,-5)
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