Question

Find the least no of saare tiles required to pave the ceiling room 15m17cm long and 9m2cm broad

Answer 1

Length of the ceiling of a room 
=> 15 m 17 cm 
=> 15 m = 15 * 100 = 1500 cm
=> 1500 cm 17 cm

==> 1500 + 17 = 1517 cm.

Broad of the ceiling of a room 
=> 9 m 2 cm 
=> 9 m = 9 * 100 = 900 cm
=> 900 cm 2 cm

==> 900 + 2 = 902 cm.

Then find the HCF of the 1517 and 902 (size of square tiles).

=> 1517, 902 = 41, 37 = 41 cm.

Area of the room 
=> length * breadth = 1517 * 902 cm^2.

Area of tiles 
=> 41 * 41 cm^2

So, no. of tiles required = (1517 * 902) / (41 * 41) = 1368334 / 1681 = 814 tiles.