Find the least no which is exactly divisible by each one of the no 12 16 and 24
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First we have to find the L.C.M of 12,16,24,36
L.C.M by prime factorization method
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
Add remainder 7 to the L.C.M = 144+7= 151
The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151
L.C.M by prime factorization method
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
Add remainder 7 to the L.C.M = 144+7= 151
The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151
Answered by
0
The least number is 151.
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