Question

Find the least number by which 3528 must be divided to get a perfect square

Answer 1

1)Firstly, factorize 3528.
3528 = 2 * 2 * 2 *3 * 3 * 7 * 7.
Now we know that a perfect square should have a pair of two prime factor.
This number has 1 pair of 2, 1 pair of 3, 1 pair of 7 and 1 alone factor 2.
Therefore, this number has a 2 less. So, 2 must be multiplied in 3528 to get a perfect square.

2)Firstly, factorize 5000.
5000 = 2 * 2 * 2 * 5 * 5 * 5 * 5.
Now we know that a perfect cube should have a pair of three prime factor.
This number has 1 pair of 2, 1 pair of 5 and 1 alone factor 5.
Therefore, this number has a 5 more. So, 5 must be divided in 5000 to get a perfect cube.

3)Firstly, factorize 180.
180 = 2 * 2 * 3 * 3 * 5.
Now we know that a perfect square should have a pair of two prime factor.
This number has 1 pair of 2, 1 pair of 3 and 1 alone factor 5.
Therefore, this number has a 5 more. So, 5 must be divided in 180 to get a perfect square.

Read more on Brainly.in - https://brainly.in/question/16280#readmore

Answer 2

the number is 2

As when you prime factorise 3528 the only number which does not form a pair is 2

HOPE THIS WOULD HELP YOU !!!