find the least number by which each of the following numbers must be multiplied to obtain a perfect cube. write cube root of the number so obtained
1:-1944
Answers
Answered by
2
==================
Solution:
(i) Prime factors of 243 = (3 × 3 × 3) × 3 × 3
Here, two 3s are left which are not in a triplet. To make 243 a cube, one more 3 is required.so, we multiply 243 by 3 to make it a perfect cube.
Similar questions